h^2+7h=168

Solution for h^2+7h=168 equation:

h^2+7h=168

We move all terms to the left:

h^2+7h-(168)=0

a = 1; b = 7; c = -168;
Δ = b2-4ac
Δ = 72-4·1·(-168)
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{721}}{2*1}=\frac{-7-\sqrt{721}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{721}}{2*1}=\frac{-7+\sqrt{721}}{2}
$